A 120-V electrical immersion heater is designed to heat 400 mL of water for tea in a glass cup in 3.00 minutes, starting from a water temperature of 20.0 degree C and heating it to 90.0 degree C. The heater is 50.0% efficient. The glass cup has a mass of 150 grams and a specific heat of 840 J/kg. degree C.

1 What is the mass of water in the cup?

2 How much total heat energy, is needed to heat the water and the glass cup from 20.0 degree C to 90.0 degree C?

3 Since the heater only 50.0% efficient, your answer to Part B is only 50.0% of the actual, total energy, E, expended by the heater. What is the value for E?

4 How much total power is supplied by the heater in 3.00 minutes?

5 How much current flows through the heater?

6 What is the resistance of the heater?

7 How strong is the magnetic field at a distance of 3cm from the heater?