A 12-foot long trough (shaped as a triangular prism) has a cross section that is an isosceles triangle, 4 feet across the top and 4 feet in height. Water is being pumped into the trough at a rate of 5 ft/sec. Find the rate at which the depth (d) of 12 the water level is when d = 10/3 feet. V = wd. 12 4 4 Hint: If 4 W = then w = d; d- W 5 ft/sec Get V in terms of d only. dd = dt [ ? ] ft/sec Round your answer to the nearest thousandth. Enter