A 150-kg mass is suspended by wires from two hooks. (See Figure 3.28.) The lengths of the wires have been adjusted so that the wires are each 50 from hor- izontal. Assume that the mass of the wires is negligible. (a) Since two hooks support the mass equally, the vertical component of force exerted by either hook will be equal to the force resulting from 75 kg being acted on by gravity. Calculate this vertical component of force, fy, on the right hook. Express your result in newtons. (b) Compute the horizontal component of force, fh, by using the result ob- tained in problem (a) and trigonometry. (c) Determine the force exerted on the mass in the direction of the wire FR. (equal to the tension in the wire). (d) If you moved the hooks farther apart to reduce the angle from 50 to 30, would the tension in the wires increase or decrease? Why? 150 kg 50" [. C F 50"