Answered step by step
Verified Expert Solution
Question
1 Approved Answer
A 18.6-g piece of gold (s ) = ( 0.129(J)/(gdeg C)) , initially at 285.4deg C , is add ded_(d) 147.2g of a liquid, initially
A 18.6-g piece of gold
(s
)
=
(
0.129(J)/(g\\\\deg C))
, initially at
285.4\\\\deg C
, is add
ded_(d)
147.2g
of a liquid, initially at
27.9\\\\deg C
, in an insulated container. The final temperature of the metal-liquid mixture at equilibrium is
28.9\\\\deg C
. What is the identity of the liquid? Negle\ a. ethanol
(s
)
=
(
2.43(J)/(g*\\\\deg C))
\ b. water
(s
)
=
(
4.53(J)/(g*\\\\deg C))
\ d. acetone
(s
)
=
(
2.15(J)/(g*\\\\deg C))
\ e. hexane
(s
)
=
(
2.27(J)/(g*\\\\deg C))
Step by Step Solution
There are 3 Steps involved in it
Step: 1
Get Instant Access to Expert-Tailored Solutions
See step-by-step solutions with expert insights and AI powered tools for academic success
Step: 2
Step: 3
Ace Your Homework with AI
Get the answers you need in no time with our AI-driven, step-by-step assistance
Get Started