A $2\mathrm{.}45$ g

lead weight, initially at $10\mathrm{.}8$C

$,$ is submerged in $7\mathrm{.}55$ g

of water at $56\mathrm{.}3$C

$,$ in an insulated container.

Part A

What is the final temperature of both substances at thermal equilibrium? The specific heat capacity for lead is $0\mathrm{.}128$ J$/($g$$C$)$

and that for water is $4\mathrm{.}184$ J$/($g$$C$)$

$.$

Express your answer in degrees Celsius to three significant figures.