A 2000 kg car starts with a velocity of 25 m/s Forward, and after 3 seconds the car has a velocity of 10 m/s Forward. A) Find the Av of the car: AV=VF-VI 10-25 B) Find the acceleration of the car: m 10-25m - - 15 50^ 3 A=Y A5 a = -5 m 3 Assume the acceleration remains constant. C) What is the Net Force acting on the car? 2000 Kg - 3 m/ 32 VF = 0 a = -5 m/ D) At what time will the car be at rest? V = 0 VIzt25m Vf=VI ta st At=55 Av=-15 m = = 10,000 N + = f -= Backward E) What distance will the car have traveled from the time it started until the time it comes t rest? Ax= v At + = ast VI - 25 m Ax = 25 m +53 + 0.5-5m (55) Vf=0m 125 m +-2.5 m 25s F) Find the velocity of the car after 20 seconds. 125 mt - 62,5 m At = 20: AX=VI ast VI-25m m = +622 VF = 25m VF=0m G) Is the car faster or slower than when it started? Explain your answer.