Question: A 22.0 m long aluminum cable with a cross-sectional area of 2.01 103 m2 is used to suspend a 3.80 103 kg container.

A 22.0 m long aluminum cable with a cross-sectional area of 2.01 ✕ 10−3 m2 is used to suspend a 3.80 ✕ 103 kg container. By how much will the cable stretch (in m) once bearing the load? (Young's modulus for aluminum is Y = 7.0 ✕ 10¹⁰Pa.)

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