Question
A 22.0 m long aluminum cable with a cross-sectional area of 2.01 103 m2 is used to suspend a 3.80 103 kg container.
A 22.0 m long aluminum cable with a cross-sectional area of 2.01 ✕ 10−3 m2 is used to suspend a 3.80 ✕ 103 kg container. By how much will the cable stretch (in m) once bearing the load? (Young's modulus for aluminum is Y = 7.0 ✕ 1010 Pa.)
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Economics
Authors: Campbell R. McConnell, Stanley L. Brue, Sean M. Flynn
18th edition
978-0077413798, 0-07-336880-6, 77413792, 978-0-07-33688, 978-0073375694
