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A 3 L glass container is partially filled with V w = 1 L of pure water. The remaining 2 L contains clean air (

A 3L glass container is partially filled with Vw=1L of pure water. The remaining 2L contains
clean air ({:P=1(atm),(T)=25C). Solid iron sulfide ( FeS(s)) is added to the water in sufficient
quantity so that some solid will remain in the system at equilibrium. The container is quickly sealed
before any reactions occur. Iron sulfide dissolves to Fe2+ and S2-. The sulfide participates in acid-
base chemistry, combining with protons to form both HS-and H2S(aq). The aqueous hydrogen
sulfide can escape into the gas phase as H2S(g).
FeS(s)harrFe2++S2-,Ksp=4.910-18
H2S(aq)harrH++HS-,Ka1=110-7
HS-harrH++S2-,Ka2=6.210-8
The Henry's constant for H2S is 0.115molL?atm
Ideal gas law: PV=nRT,R=0.08205atmLmole-1K-1
(a) Identify all the unknowns in the system (both water and air phase).(3 pts).
(b) Write a complete set of algebraic equations to solve for the equilibrium pH of the water. (8 pts)
(c) Solve the above set of equations using EES, Excel, Maple, or equation solver of your choice. (5
pts)
(d) In water phase, what proportion of the total sulfides (S2-, HS-, H2S) is in the completely
unprotonated form of sulfide, at equilibrium? If you cannot figure out how to solve part (c), then
guess a pH in order to calculate this proportion. Your guess should be reasonable! (5 pts)
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