A 3.77 kg particle has the xy coordinates (-1:49 m, 0.477 m), and a 2.94 kg particle has the xy coordinates (0.0585 m, -0.339 m). Both lie on a horizontal plane. At what (a) x and (b) y coordinates must you place a 2.88 kg particle such that the center of mass of the three- particle system has the coordinates (-0.388 m, -0.894 m)?