A 50-kilowatt gas turbine has an investment cost of $42,000. It costs another $16,000 for shipping, insurance, site preparation, fuel lines, and fuel storage tanks. The operation and maintenance expense for this turbine is $550 per year. Additionally, the hourly fuel expense for running the turbine is $7.75 per hour, and the turbine is expected to operate 2,500 hours each year. The cost of dismantling and disposing of the turbine at the end of its. 6-year life is $7,500. a. If the MARR is 16% per year, what is the annual equivalent life-cycle cost of the gas turbine? b. What percent of annual life-cycle cost is related to fuel? Click the icon to view the interest and annuily table for discrete compounding when the MARR is 16% per year. a. The annual equivalent life-cycle cont of the gas turbine is s (Round to the nearest dollar) \begin{tabular}{|c|c|c|c|c|c|c|} \hline & & Discreto & ompounding: & f=16% & & \\ \hline & Single & Payment & & Uniform & Series & \\ \hline & \begin{tabular}{l} Compound \\ Amount \\ Factor \end{tabular} & \begin{tabular}{c} Present \\ Worth Factor \end{tabular} & \begin{tabular}{l} Compound \\ Amount \\ Factor \end{tabular} & \begin{tabular}{l} Present \\ Worth Factor \end{tabular} & \begin{tabular}{l} Sinking \\ Fund \\ Factor \end{tabular} & \begin{tabular}{c} Capital \\ Rocovery \\ Factor \end{tabular} \\ \hline N & \begin{tabular}{l} To Find F \\ Glven P \\ FP \end{tabular} & \begin{tabular}{c} To Find P \\ Given F \\ PIF \end{tabular} & \begin{tabular}{c} To Find F \\ Given A \\ FlA \end{tabular} & \begin{tabular}{c} To Find P \\ Given A \\ PIA \end{tabular} & \begin{tabular}{l} To Find A \\ Given F \\ A/F \end{tabular} & \begin{tabular}{c} To Find A \\ Glven P \\ A/P \end{tabular} \\ \hline 1 & 1.1600 & 0.8621 & 1.0000 & 0.8621 & 1.0000 & 1.1600 \\ \hline 2 & 1.3456 & 0.7432 & 2.1600 & 1.6052 & 0.4650 & 0.6230 \\ \hline 3 & 1.5609 & 0.6407 & 3.5056 & 2.2459 & 0.2853 & 0.4453 \\ \hline 4 & 1.8106 & 0.5523 & 5.0665 & 2.7982 & 0.1974 & 0.3574 \\ \hline 5 & 2.1003 & 0.4761 & 6.8771 & 3.2743 & 0.1454 & 0.3054 \\ \hline 6 & 2.4364 & 0.4104 & 8.9775 & 3.6847 & 0.1114 & 0.2714 \\ \hline 7 & 2.8262 & 0.3538 & 11.4139 & 4.0386 & 0.0876 & 0.2476 \\ \hline 8 & 3.2784 & 0.3050 & 14.2401 & 4.3436 & 0.0702 & 0.2302 \\ \hline 9 & 3.8030 & 0.2630 & 17.5185 & 4.6065 & 0.0571 & 0.2171 \\ \hline 10 & 4.4114 & 0.2267 & 21.3215 & 4.8332 & 0.0469 & 0.2069 \\ \hline \end{tabular} Print Done A 50-kilowatt gas turbine has an investment cost of $42,000. It costs another $16,000 for shipping, insurance, site preparation, fuel lines, and fuel storage tanks. The operation and maintenance expense for this turbine is $550 per year. Additionally, the hourly fuel expense for running the turbine is $7.75 per hour, and the turbine is expected to operate 2,500 hours each year. The cost of dismantling and disposing of the turbine at the end of its. 6-year life is $7,500. a. If the MARR is 16% per year, what is the annual equivalent life-cycle cost of the gas turbine? b. What percent of annual life-cycle cost is related to fuel? Click the icon to view the interest and annuily table for discrete compounding when the MARR is 16% per year. a. The annual equivalent life-cycle cont of the gas turbine is s (Round to the nearest dollar) \begin{tabular}{|c|c|c|c|c|c|c|} \hline & & Discreto & ompounding: & f=16% & & \\ \hline & Single & Payment & & Uniform & Series & \\ \hline & \begin{tabular}{l} Compound \\ Amount \\ Factor \end{tabular} & \begin{tabular}{c} Present \\ Worth Factor \end{tabular} & \begin{tabular}{l} Compound \\ Amount \\ Factor \end{tabular} & \begin{tabular}{l} Present \\ Worth Factor \end{tabular} & \begin{tabular}{l} Sinking \\ Fund \\ Factor \end{tabular} & \begin{tabular}{c} Capital \\ Rocovery \\ Factor \end{tabular} \\ \hline N & \begin{tabular}{l} To Find F \\ Glven P \\ FP \end{tabular} & \begin{tabular}{c} To Find P \\ Given F \\ PIF \end{tabular} & \begin{tabular}{c} To Find F \\ Given A \\ FlA \end{tabular} & \begin{tabular}{c} To Find P \\ Given A \\ PIA \end{tabular} & \begin{tabular}{l} To Find A \\ Given F \\ A/F \end{tabular} & \begin{tabular}{c} To Find A \\ Glven P \\ A/P \end{tabular} \\ \hline 1 & 1.1600 & 0.8621 & 1.0000 & 0.8621 & 1.0000 & 1.1600 \\ \hline 2 & 1.3456 & 0.7432 & 2.1600 & 1.6052 & 0.4650 & 0.6230 \\ \hline 3 & 1.5609 & 0.6407 & 3.5056 & 2.2459 & 0.2853 & 0.4453 \\ \hline 4 & 1.8106 & 0.5523 & 5.0665 & 2.7982 & 0.1974 & 0.3574 \\ \hline 5 & 2.1003 & 0.4761 & 6.8771 & 3.2743 & 0.1454 & 0.3054 \\ \hline 6 & 2.4364 & 0.4104 & 8.9775 & 3.6847 & 0.1114 & 0.2714 \\ \hline 7 & 2.8262 & 0.3538 & 11.4139 & 4.0386 & 0.0876 & 0.2476 \\ \hline 8 & 3.2784 & 0.3050 & 14.2401 & 4.3436 & 0.0702 & 0.2302 \\ \hline 9 & 3.8030 & 0.2630 & 17.5185 & 4.6065 & 0.0571 & 0.2171 \\ \hline 10 & 4.4114 & 0.2267 & 21.3215 & 4.8332 & 0.0469 & 0.2069 \\ \hline \end{tabular} Print Done
