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A 64.3 mg sample of a protein (MW = 58,600) was treated with 2.00 mL of 0.0487 M sodium periodate (NaIO4) to selectively react

A 64.3 mg sample of a protein (MW = 58,600) was treated with 2.00 mL of 0.0487 M sodium periodate (NaIO4) to selectively react with all of the serine and threonine residues. The resulting solution was then treated with excess iodide ion to convert the unreacted periodate into triiodide ion (13). 10 +31 + HO 103 + 13 + OH A microtitration of the triiodide ion required 823 L of 0.0988 M thiosulfate. 2 S031331+S406 Calculate the total number of serine + threoine residues per molecule of protein.

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