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A 8.90 kg particle with velocity (5.08 m/s ) - (3.12 m/s ) is at x = 8.93 m, y = 4.02 m. It

 

A 8.90 kg particle with velocity (5.08 m/s ) - (3.12 m/s ) is at x = 8.93 m, y = 4.02 m. It is pulled by a 9.43 N force in the negative x direction. About the origin, what are (a) the particle's angular momentum, (b) the torque acting on the particle, and (c) the rate at which the angular momentum is changing? =

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