a and b.

(3) Remember the room from exam 1? If not, that's ok. The important thing is that the temperature in the room was given by 324 Tx,,z= (y) 4+x2+y2+z2 and our friend, Student, was sitting at the point (1, 1, 0), In exam 1, you computed for Student the directions along which the temperature increases. Since Student can't take the summer heat anymore, he decided to go opposite to what you suggested and he is now and the point (1, 2, 0). (a) What's the temperature at the point (1, 2, O)? (b) What's the direction Student should go (from the point (1, 2, 0)) so that the temperature will decrease most rapidly? (c) As much as Student wants to stay away from the summer heat, Student doesn't want to suffer from hypothermia. Find all unit directions starting at (1, 2, 0) along which the temperature will increase by roughly 8 degrees and for which Student won't have to climb anything. More precisely, nd all unit vectors 0 = (121, 02, 0) such that VUT(1, 2, 0) = 8. Here, the last component of U is zero because we don't want Student to climb anything. It's been almost a month he is stuck in the room and Student is tired