A B C 32 45 32 30 44 35 30 45 34 26 47 35 32 49 39 Sample mean 30 46 35 Sample variance 6.00 4.00 6.50 a. At the a = 0.05 level of significance, can we reject the null hypothesis that the means of the three treatments are equal? Compute the values below (to 1 decimal, if necessary). Sum of Squares, Treatment 0 Sum of Squares, Error 0 Mean Squares, Treatment 6 Mean Squares, Error 0 Calculate the value of the test statistic (to 2 decimals). What is your conclusion? ' Conclude that not all treatment means are equal V' w b. Calculate the value of Fisher's LSD (to 2 decimals). Q b. Calculate the value of Fisher's LSD (to 2 decimals). 0 Use Fisher's LSD procedure to test whether there is a significant difference between the means for treatments A and B, treatments A and C, and treatments B and C. Use a = 0.05. Difference Absolute Value Conclusion TA 53 0 Significant difference v Q0 EA EC 0 Significant difference v Q0 53 EC 0 Significant difference v M c. Use Fisher's LSD procedure to develop a 95% confidence interval estimate of the difference between the means of treatments A and B (to 2 decimals). Enter negative values as negative numbers.