A ball is dropped from a rooftop onto level ground below at time t = 0. A moment later a second ball is thrown downward from the same height with an initial (downward) velocity vo. The graph shows the approximate paths of the two balls versus time. The first ball lands in 2.4 s while the second ball lands 0.25 seconds later. What was the initial speed of the ball if the second ball was thrown down 1.1 seconds after the first one was dropped? Recall that for "speed" we use absolute value. = 7.595 x m/s Hint: Both balls fall through the same height. If you are given the time that ball 1 falls (from rest), you can calculate this height. From the times given, you can find the time it took for the second ball to fall the same distance. Remember that both balls accelerate at the same rate. This provides enough information to calculate the initial speed of the second ball (using a constant acceleration equation). Time (s) t1 t1+At