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A ball of mass 0.440 kg moving east( + x direction) with a speed of 3.30m/s collides head-on with a 0.220-kg ball at rest. If

A ball of mass 0.440 kg moving east( + x direction) with a speed of 3.30m/s collides head-on with a 0.220-kg ball at rest. If the collision is perfectly elastic, what will be the speed and direction of each ball after the collision? (Hint: the relationship of the velocities before and after the collision is v1i-v2i = v2f - v1f. This equation may be useful if you have two unknowns in an equation)

a. Solve for v2f in terms of v1f using the provided information

b. Using the law of conservation of momentum, substitute your answer from part (a) and solve for the final velocity of the first ball.

c. Solve for the final velocity of the second ball.

PLEASE SHOW ALL WORK LEGIBLY, THANK YOU!

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