Question
A baseball player's batting average is 0.348, which can be interpreted as the probability that he got a hit each time at bat. Thus, the
A baseball player's batting average is 0.348, which can be interpreted as the probability that he got a hit each time at bat. Thus, the probability that he did not get a hit is
1−0.348=0.652. Assume that the occurrence of a hit in any given at-bat has no effect on the probability of a hit in other at-bats. In one game, the player had 4 at-bats. What is the probability that he had 2 hits?
s?
What expression can be used to calculate the probability? 4 OA. [2] (0.348) (0.652) B. 4 [2] 10 O D. (0.348 +0.652) 4 Oc. [2] (0.348)4 (0.652) 6 [8] (0.3 4 (0.348)4 (0.652)4 The probability that the player had 2 hits in 4 at-bats is (Round to three decimal places as needed.)
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Giventhe probability that he got a hit each time at bat is 0348 ie p0348 And the probabilit...Get Instant Access to Expert-Tailored Solutions
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Finite Mathematics and Its Applications
Authors: Larry J. Goldstein, David I. Schneider, Martha J. Siegel, Steven Hair
12th edition
978-0134768588, 9780134437767, 134768582, 134437764, 978-0134768632
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