A basketball is thrown at 45 to the horizontal. The hoop is located 3.7m away horizontally at a height of 1.1m above the point of release. What is the required initial speed?

In thind Page tanysoz 1 we g cot 1 gn 2 2 by 2 Ceas 29 = h sang-y firstly there way putting nature. mistake in/ calculation ( 9 . 8 m/ s 2 ) ( 3 . 7 m ) 2 X := ( 3 . 7 4on 45 - 1 . 1) 0 9. 8 x (307 ) 2 mas X 2 (3 .7 ( 1 ) - 1 . 1 ) m vo' ( 1/52 ) 2 ( 9 . 8 ) ( 13 . 69 ) m 3 5 2 X 2 . 6 m Vo ( 1 ) 9.8 ) ( 13. 69 ) m 2 / s ? 134 . 1 6 2 Voz m/ s 2 . 6 VOZ 51-6 s / w Vo E 70183 m/s initial velocity V. = 7.183 m/s