Question
A basketball player jumps straight up for a ball. he lowers his body 0.31 m and then accelerates through this distance by forcefully straightening his
A basketball player jumps straight up for a ball. he lowers his body0.31m and then accelerates through this distance by forcefully straightening his legs. This player leaves the floor with a vertical velocity sufficient to carry him0.88m above the floor. For this problem, use a coordinate system where up is positive. Part (a)Calculate his velocity when he leaves the floor in m/s. PART B: Calculate his acceleration, in m/s2, while he is straightening his legs. He goes from zero to the velocity found in part (a) in a distance of 0.31 m. PART C: Part (c)Calculate the magnitude of the force he exerts on the floor to do this, in newtons, given that his mass is 110 kg. I only need help with B and C. Thank you!
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