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A basketball player jumps straight up for a ball. To do this, he lowers his body 0.315 m and then accelerates through this distance by

A basketball player jumps straight up for a ball. To do this, he lowers his body 0.315 m and then accelerates through this distance by forcefully straightening his legs. This player leaves the floor with a vertical velocity sufficient to carry him 0.895 m above the floor.

 ( a ) Calculate his velocity ( in m / s ) when he leaves the floor. m / s

 ( b ) Calculate his acceleration in m / s 2 , while he is straightening his legs. He goes from zero to the velocity found in part ( a ) in a distance of 0 .315 m . m / s 

( c ) Calculate the force ( in N ) he exerts on the floor to do this, given that his mass is 114 kg . 


 

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a To calculate the velocity when the player leaves the floor we can use the kinematic equation v u 2... blur-text-image

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