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A basketball star covers 2.50 m horizontally in a jump to dunk the ball. His motion through space can be modeled precisely as that
A basketball star covers 2.50 m horizontally in a jump to dunk the ball. His motion through space can be modeled precisely as that of a particle at his center of mass. His center of mass is at elevation 1.02 m when he leaves the floor. It reaches a maximum height of 1.80 m above the floor and is at elevation 0.950 m when he touches down again. (a) Determine his time of flight (his "hang time"). S (b) Determine his horizontal velocity at the instant of takeoff. m/s (c) Determine his vertical velocity at the Instant of takeoff. m/s (d) Determine his takeoff angle. above the horizontal (e) For comparison, determine the hang time of a whitetail deer making a jump with center-of-mass elevations y, = 1.20 m, Ymax = 2.45 m, and y = 0.750 m. S
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A fun problem Lets break it down step by step a Time of flight hang time The center of mass starts at 102 m and ends at 0950 m The maximum height is 1...Get Instant Access to Expert-Tailored Solutions
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