A basketball was thrown upward. The basketball's path is given the by function h=-0.2(d-2.5)^2 + 4.25 where h is he basketball's height above the ground and d is the basketball's horizontal distance from where it was thrown in meters. a) What was the basketball's initial height above the ground? Hint: the y-intercept - to find this set x = 0 and solve for y. it is not 4.25. A/ b) What was the basketball's greatest height above the ground? c) What was the basketball's horizontal distance at this point? A A/ d) the basketball was thrown toward a net 6 m away and 3 m above the ground. Will the basketball go through the net? 5 f(x)=-0.2(x-2.5)+4.25 3: 2 10 Question 1 (3 points) 10 10 49 f(x)=-(4)-(x-5)+25 20 40 60 80 Problem #1: A soccer ball is kicked from the ground. When it has travelled 35 m horizontally it reaches its maximum height of 25 m. The soccer ball lands on the ground 70 m from where it was kicked. It is modelled by the graph shown. It is also modelled by this equation x represents the horizontal distance and y represents the vertical distance. y=-(1/49)(x-35) +25 a) What is the maximum height (y) the ball reached? b) What was the x value (the value along the x axis) when the maximum height is reached? A c) What was the soccer's height when it was 50 m from where it was kicked. Rounded to the nearest whole number. A