A beam of polarised light with intensity I0 is incident on a series of 2 polarising sheets. The first polarising sheet is at an angle of ? to the initial polarisation of the beam. The second polarising sheet is at an angle of 90 to the initial polarisation of the beam. If the final intensity of the light is 0.18I0, what is the angle ?? The answer should be in degrees

it is given that incident light is already polarised initially On passing musough first polariser its intensity will be given by malus law. . as follows I = I. COSO I, P2 Now, angle between Two polarisers = 90-0 Hence final intensity 12 = I , cos ( 90 - @ ) 12 = [, sino Iz = (To Cos ?@ ) ( sin 20 ) [2 = To ( sino coso ) ? = 0-18 I . ( sino cosco ) = 0.18 sino coso = 0. 4243 2 sino Cosco = 0. 8486 Sin20 = 0. 8486 C: 2 sino cosco = Sin 20] 20 = SIX (O. 84 86 ) 20 = 58.06' 0 = 29.03