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A billiard ball moving at 5.90 m/s strikes a stationary ball of the same mass. After the collision, the first ball moves at 4.83 m/s,

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A billiard ball moving at 5.90 m/s strikes a stationary ball of the same mass. After the collision, the first ball moves at 4.83 m/s, at an angle of @ = 35.00 with respect to the original line of motion. Assuming an elastic collision (and ignoring friction and rotational motion), find the struck ball's velocity after the collision. Part 1 of 5 - Conceptualize We guess a bit less than 3 m/s for the speed of the struck ball at an angle of about -60. Part 2 of 5 - Categorize We apply conservation of momentum to the x and y components of velocity in the two-ball system. Part 3 of 5 - Analyze We are given the following information about the x and y components of velocity before and after the collision. We know that 1ix = 5.90 m/s, "liy = 0, V2ix = 0, V2iy 1fx = (4.83 m/s) cos 35 ify = (4.83 m/s) sin 35 Let's call the value of mass for each ball m, and let Vor represent the velocity of the second ball after the collision, as in the figure. In the x direction, conservation of momentum for the two-ball system gives the following. my lix + my 2ix = MV 1fx + my 2fx So, we have V2fx = Vlix + 2ix - V1fx = 1.9435 Your response differs from the correct answer by more than 10%. Double check your calculations. m/s ) + 0 - (2.7704 x Your response differs from the correct answer by more than 10%. Double check your calculations. m/s ) cos |298.276 1x The response you submitted has the wrong sign. " giving V26 = 3.145 Your response differs from the correct answer by more than 10%. Double check your calculations. m/s.A 9.900-g bullet is fired into a stationary block of wood having mass m = 4.970 kg. The bullet imbeds into the block. The speed of the bullet-plus-wood combination immediately after the collision is 0.6030 m/s. What was the original speed of the bullet? (Express your answer with four significant figures.) 40 303.3212 1x Note that after the collision the bullet is imbedded in the block so that both are moving with the velocity 0.603 m/s. Check the number of significant figures. m/s More Information. Need Help? Read It Watch It

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