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A black hole can be thought of as a single point. The event horizon of a black hole is the circumference of a circle centred
A black hole can be thought of as a single point. The event horizon of a black hole is the circumference of a circle centred on the black hole from which nothing, not even light, can escape. A spaceship leaving a space station will travel in the vicinity of the black hole with a trajectory of s(x) = ln(x + 1) + 15 , x 0. If the black hole is located at (15, 15), and the radius of its event horizon is 45, what is the closest approach of the spaceship to the black hole? Does the ship survive?
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