A block of mass m = 3.61kg moves along the x-axis subject to a net force which depends on position. The force is Fner(x) = (-3.76 Nx - 1.73 Nx3) i. The block is initially at x = 0m moving with velocity D = -4.14mi. (The input below will accept answers with no more than 1% variation from the correct value.) What is the smallest value of x the block reaches? m Hint: Calculate the work done as a function of x, and then solve the resulting quadratic expression for x2. What is the block's speed when it reaches x = 1.47m