Answered step by step
Verified Expert Solution
Link Copied!

Question

1 Approved Answer

A block of mass m1 : 36.2 kg on a horizontal surface is connected to a mass m2 : 13.6 kg that hangs vertically as

image text in transcribedimage text in transcribedimage text in transcribed
image text in transcribedimage text in transcribedimage text in transcribed
A block of mass m1 : 36.2 kg on a horizontal surface is connected to a mass m2 : 13.6 kg that hangs vertically as shown in the figure below. The two blocks are connected by a string of negligible mass passing over a frictionless pulley. Assume that the horizontal surface is smooth. (a) What is the acceleration (in m/sz) of the hanging mass? (Enter the magnitude only.) 0,957 x Did you draw a free body diagram for each of the two masses and identify all the forces acting on them? mfs2 (b) Determine the tension (in N) in the cord. (Enter the magnitude only.) x ConSider Newton's second law for Either one of the two rnasses to find the tension. N In the figure below the two blocks are connected by a string of negligible mass passing over a frictionless pulley. m1 : 10.0 kg and :312 : 3.00 kg and the angle of the incline l5 9 : 45.0\". Assume that the incline is smooth. (Assume the +X direction is down the incline of the plane.) (a) With what acceleration (in mlsz) does the mass m x Did you draw a free body diagram for each mass and label all forces? For m2 take the positive X direction to be down the incline plane. Consider Newton's second law for each mass separately. rn/S2 2 move on the incline surface? Indicate the direction with the sign of your answer. (b) What is the tension in the string in newtons? 1573 x Consider motion of either one of the two masses to find the tension. N (c) For what value of mi (in kg) will the system be in equilibrium? 21:2 kg Sphere A is attached to the ceiling of an elevator by a string. A second sphere is attached to the first one by a second string. Both strings are of negligible mass. Here m1 : m2 : m : 3.25 kg. (a) The elevator starts from rest and accelerates downward with a = 1.35 m/sz. What are the tensions in the two strings in newtons? T1 : E N T; = S N (b) If the elevator moves upward instead with the same acceleration what will be the tension in the two strings in newtons? T1 = E N H = S N (c) The maximum tension the two strings can withstand is 89.3 N. What maximum upward acceleration (in m152) can the elevator have without having one of the strings break? :W

Step by Step Solution

There are 3 Steps involved in it

Step: 1

blur-text-image

Get Instant Access to Expert-Tailored Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image

Step: 3

blur-text-image

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started

Recommended Textbook for

Fluid Mechanics

Authors: Russell C. Hibbeler

2nd Edition

134676610, 978-0134676616

More Books

Students also viewed these Physics questions

Question

In a payroll system, which duties should be separated?

Answered: 1 week ago