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A bomber is flying horizontally at an altitude of 3200 feet with a velocity of 400 ft per second. A projectile is launched 5 seconds
A bomber is flying horizontally at an altitude of 3200 feet with a velocity of 400 ft per second.
A projectile is launched 5 seconds later from a cannon at a site facing away from the bomber and 5000 ft from the point that was directly beneath the bomber when the bomb was released. The projectile is to intercept the bomb at an altitude of 1600 ft. Determine the required initial speed and angle of inclination of the projectile
4000 3200 - - - - Bomb 1600- - - - - - - - - = = - Projectile + Cannon 5000Step by Step Solution
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