A bullet of mass my hits a wooden block of mass my horizontally at a speed v1. The bullet remains in the block after massless string of length L before the collision. The bullet-block system swings up after the collision. Let m1 = 12.0000 g, m2 = 0.8500 kg, v1 = 175.0000 m/s and L = 55.0000 cm. Use the initial height of the block as the origin. Remember, if you want to get the correct answers, you will need to use g = 9.80 m/s?! A) What is the speed of the wooden block immediately after the collision, in m/s and to three decimal places? B) What is the mechanical energy of the bullet-block immediately after the collision, in J and to three decimal places? C) What is the moment of inertia of the bullet-block system when it is at an angle of 25.0000 degrees with respect to the vertical, in kg . my and to three decimal places? If the bullet-block system has no moment of inertia, then enter '0' as your answer in the appropriate form.) D) What is the angular speed of the bullet-block system when it is 25.0000 degrees with respect to the vertical, in rad/s and to three decimal places? (If the bullet-block system has no angular speed, then enter 'O' in the appropriate form.) E) What is the tension in the string when the bullet-block system is at 25.0000 degrees with respect to the vertical, in N and to three decimal places