A cable with mass 360 kilograms and length 150 meters is suspended down a deep well. Recall, the variable force F(x) exerted by the remaining cable, after x meters of cable have been lifted, is F(x)=mg (1-x/L), where m is the total mass of the cable, L is the length, and g = 9.8 m/s is acceleration due to gravity. a) Find the work, in Joules, required to lift the entire cable. b) Find the work, in Joules, required to lift just the first 60 meters of cable. c) Set up an integral (you don't need to evaluate it) that represents the work required to lift just the last 60 meters of cable.