A cane is used to help shift the weight off of an injured leg, thereby reducing the stress whilst walking. Normally, the centre of mass would need to be directly over the right leg during a portion of a person's gait to prevent them from toppling over. But, with a cane, the center of mass is able to shift a distance x towards the left leg. removing some of the burden. Calculate x, assuming that the normal force acting on the cane, FC, equals 1/6 of the body weight, and that the remaining weight is supported entirely by the right leg. The cane is located a distance d1 = 29.8 cm from the person's centre of mass. The length of the leg is L = 0.82 m and the person weighs Wb = 514 N. Report your answer in units of cm, rounded to the nearest tenths place. FM femr FA acetabulum *Wb d sacrum Attached via arm and shoulder w/6 y 70 d3 W X F = w/6