A cannon in a fort is 18.4 m above the ground, and it fires a cannonball with an initial velocity of 72.4 m/s at a 34 angle above the horizontal. How far from the base of the fort wall does the cannonball strike the ground? Hint: you can't use twice the time to reach the peak of flight as the total flight time because the cannon is above ground level. One method to solve this problem is to calculate the time of flight using d = sat' + vit, using the vertical velocity vy for vi, and solve for t with the quadratic equation (or by completing the square, or by getting vy first). Then solve for distance in the usual manner using the horizontal velocity vr