A car of mass 1500kg travels in a circle of radius 50m at a speed of 20m. It is on a track that is banked (sloped) towards the inside of the curve at an angle of 15 with the horizontal. The coefficient of static friction between the car and the slope is u = 0.70. 150 22. What is the magnitude of the net force on the car? (a) 0.27 x 104 N (b) 0.99 x 104 N (c) 1.03 x 104N (d) 1.20 x 104 N (e) 1.47 x 104 N 23. The equation we obtain by considering the vertical component of New- ton's second law is FN 0 = cos 15 m sin 15 - g m (1) What equation do we obtain by considering the horizontal component of Newton's second law? (a) - lal = _LEN sin 15 _ Fil m cos 15 (b) - lal = _LEN sin 15 + FAl m. cos 15 (c) - lal = EN m sin 15 - m cos 15 (d) - la| = EN sin 15 + Ff cos 15 (e) - lal = _ LEN cos 15 + Ff sin 15 24. What is the magnitude of the friction force on the car? (a) 0.78 x 104N (b) 0.95 x 104 N (c) 1.23 x 104 N (d) 1.73 x 104 N (e) 2.51 x 104 N 25. The car's speed || increases. What happens to the magnitudes of the normal and friction forces? (a) FN decreases and Ff decreases. (b) FN decreases and Ff increases. (c) FN increases and Ff decreases. (d) FN increases and Ff remains constant. (e) FN increases and Ff increases