A certain gas is known to have a pressure of 9 psi. We are asked to take measurements using two different sensors. These are the results that we obtained after measuring the pressure of the gas 7 different times. Sensor 1: 9.8 10.0 10.3 9.7 9.9 10.1 9.8 Sensor 2: 9.3 9.5 8.6 9.0 8.9 9.2 8.5 Do you believe one of the sensors is more accurate than the other? What about precise? Explain your reasoning. Points to Consider Percent error: This is the difference between the measured value and the real value divided by the real value. As we may not know the real value, most of the times we will use the accepted or estimated value. The percent error can be written as: Percent Error (96) = Measured Value - Accepted value | x 100 Accepted Value The |Measured Value - Accepted Value] means the absolute value between these two numbers; this means to omit the sign. Example: Measuring a 1.5 V battery twice gives the following readings: 1.63 V and 1.37 V. Calculate the percent error of each measurement. Measurement 1: Error = 163V-15V. 100 = 4134 - 100 = 8.67% Measurement 2: Error= ! 137 V-15 100= 9134 = 100 = 8.67% Note that in both cases the percent error is the same