A certain material has a simple cubic crystal structure and an atomic mass $($A$)$ of $50\mathrm{.}5\frac{g}{m}ol$ and an atomic radius of $0\mathrm{.}15nm.$ The Avogadro's number $(N_A)$ is $6\mathrm{.}023{10}^{23}$ atoms $\frac{?}{\text{m}\text{o}\text{l}}.$ For a simple cube, the unit cell side length $a=2R.$ If the density is given as $\frac{nA}{V_c{N}_A},$ determine the density of this material in $\frac{g}{c}{m}^3\mathrm{.}1nm={10}^{-7}cm.$ Just put in the answer in the box below. Do not put in the units.