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A circuit is constructed with five resistors and one real battery as shown above right. We model. The real battery as an ideal emf V

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A circuit is constructed with five resistors and one real battery as shown above right. We model. The real battery as an ideal emf V = 12 V in series with an internal resistance r as shown above left. The values for the resistors are: R1 = R3 = 23 ('1, R4 = R5 = 137 D and R2 = 97 Q. The measured voltage across the terminals of the batery is Vbattery = 11.47 V. I] R1 13 RB 1) What is I1, the current that flows through the resistor R1? mA Submit + 2) What is r, the internal resistance of the battery? 0 Submit 4. 3) What is I3, the current through resistor R3? mA Submit 4. 4) What is P2, the power dissipated in resistor R2? W Submit \\./ 4) What is P2, the power dissipated in resistor R2? W Submit 5) What is V2, the magnitude of the voltage across the resistor R2? V Submit 6) Resistor R2 is now shorted out as shown. How does the magnitude of the voltage across the battery change? Vbattery decreases Vbattery increases Vbattery remains the same Submit

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