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A city is growing at the rate of 0.6% annually. If there were 2,795,000 residents in the city in 1992, find how many (to the

A city is growing at the rate of 0.6% annually. If there were 2,795,000 residents in the city in 1992, find how many (to the nearest ten thousand) we're living in that city in 2000. Use y =2,795,000(2.7)^0.006t.

solve the equation x^3-13x^2+47x-35=0 given that 1 is zero of f(x) x^3-13x^2+47x-35.

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