Answered step by step
Verified Expert Solution
Link Copied!

Question

1 Approved Answer

A company claims that the mean monthly residential electricity consumption in a certain region is more than 890 kiloWatt-hours (kWh). You want to test

image text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribed

A company claims that the mean monthly residential electricity consumption in a certain region is more than 890 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 65 residential customers has a mean monthly consumption of 930 kWh. Assume the population standard deviation is 124 kWh. At a = 0.10, can you support the claim? Complete parts (a) through (e). (a) Identify Ho and Ha. Choose the correct answer below. OA. Ho >930 (claim) H: 930 OC. Ho 890 Ha >890 (claim) O E. Ho H>890 (claim) H 890 OB. Ho=930 Ha 930 (claim) OD. Ho 930 H >930 (claim) OF Ho H-890 (claim) H 890 K A company claims that the mean monthly residential electricity consumption in a certain region is more than 890 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 65 residential customers has a mean monthly consumption of 930 kWh. Assume the population standard deviation is 124 kWh. At a 0.10, can you support the claim? Complete parts (a) through (e) (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology (Round to two decimal places as needed.) OA. The critical values are OB. The critical value is Identify the rejection region(s). Select the correct choice below OA. The rejection region is z> 1.28. Sav A company claims that the mean monthly residential electricity consumption in a certain region is more than 890 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 65 residential customers has a mean monthly consumption of 930 kWh. Assume the population standard deviation is 124 kWh. At a 0.10, can you support the claim? Complete parts (a) through (e). OB. The rejection regions are z 1.28. OC. The rejection region is z < 1.28. (c) Find the standardized test statistic. Use technology. The standardized test statistic is z= (Round to two decimal places as needed.). fail to rainst the null hunathacie (d) Decide whether to reject or fail to reject the null hypothesis. OA. Fail to reject Ho because the standardized test statistic is not in the rejection region. OB. Reject Ho because the standardized test statistic is in the rejection region. OC. Fail to reject Ho because the standardized test statistic is in the rejection region. OD. Reject Ho because the standardized test statistic is not in the rejection region. (e) Interpret the decision in the context of the original claim. At the 10% significance level, there is enough evidence to the claim that the mean monthly (e) Interpret the decision in the context of the original claim. At the 10% significance level, there is enough evidence to residential electricity consumption in a certain region the claim that the mean monthly kWh.

Step by Step Solution

There are 3 Steps involved in it

Step: 1

blur-text-image

Get Instant Access with AI-Powered Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image

Step: 3

blur-text-image

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started

Recommended Textbook for

Precalculus

Authors: Michael Sullivan

9th edition

321716835, 321716833, 978-0321716835

Students also viewed these Mathematics questions