A company has set up a factory to manufacture a new phone. For each production line, the rate of production of these phones is p (t) = 5000 1 - 100 (t+10)3 |phones/day. (Notice that production approaches 5000 per day as time goes on, but the initial production rate is lower because of the workers' unfamiliarity with the new techniques.) Use a graphing calculator (like Desmos) to view the graph of p (t). You'll need to adjust the window to view the relevant portion of the horizontal and vertical axis.5000 4000 -3000 -2000 1000 10 15 20 25 30 35 40Refer to the information about the function p [t] given above. For the graph ofp (t), what are the correct units for the vertical and horizontal axes? [Select ] phones I year v' phones phones I clay Horizontal axis units: days v Refer to the information about the function p (t) given above. For the graph of p (t), what are the correct units for the vertical and horizontal axes? Vertical axis units: phones V [ Select ] years v' days weeks Refer to the definition of p(t) given above. To find the number of phones produced on each production line during time interval [a, b], we can evaluate So p(t) dt [ Select ] phones / week This definite integral has units o v phones / day phones This definite integral is a typical example for the integration technique of substitution Applying an n=1 Riemann Sum to the graph of p(t), we can estimate f p(t)dt ~ [ Select ]Refer to the definition of p(t) given above. To find the number of phones produced on each production line during time interval [a, b], we can evaluate S p(t ) at This definite integral has units of phones / day [ Select ] This definite integral is a typical example for the integration technique ov substitution partial fractions Applying an n=1 Riemann Sum to the graph of p(t), we can estimate fin p(t)dt ~ [ Select ]Refer to the definition of p(t) given above. To find the number of phones produced on each production line during time interval [a, b], we can evaluate le p(t) at This definite integral has units of phones / day This definite integral is a typical example for the integration technique of substitution Applying an n=1 Riemann Sum to the graph of p(t), we can estimate fin p(t)dt = > [ Select ] 20,000 40,000 10,000