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A company owns a machine that has a current net book value of G62.700. It has not been used for several months, but it could

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A company owns a machine that has a current net book value of G62.700. It has not been used for several months, but it could now be used on a job for a customer which would last for up to six months. If the machine is not used for this job, it will be sold immediately to ar net income of GH2,900. After using the machine for the contract, it would have no further use or value, and it would have to be disposed of at a cost of GH500. What is the total relevant cost of the machine for the contract? GH&2,400 B. GH 2,700 c. GH42,900 D. GH 3,400 28. A company manufactures two products and T using the same materials and tabour. It holds no inventories. Information about the variable costs and maximum sales demand for each product are as follows: Products Product T GH per unit GH & per unit Material (GH5 per kg) 12 10 Labour (GH20 per hour) 45 30 units units Maximum sales per month 4,000 6,000 Each month a maximum of 21,500 kilograms of material and 18,200 hours of labour are available. Which one of the following statements is correct? A. Material is a limiting factor but labour is not a limiting factor Labour is a limiting factor but material is not a limiting factor C. Both material and labour are limiting factors D. Neither material nor labour is a limiting factor 29. A company manufactures and sells two products, Product X and Product Y, which can be sold for GH120 per unit and GH454 per unit respectively. Variable costs of the two products are: Product X Product Y GH per unit GHe per unit Material (GH 10 per kg) 30 10 Labour (GH12 per hour) 48 6 Other variable costs 12 14 Total 90 30 Next month only 4,700 kg of materials and 3,300 labour hours will be available. The company holds no inventory. It is committed to selling at least 700 units of Product Year month. In a linear programming problem to identify the profit-maximizing production quantities, which one of the following is a constraint? A. x+3y = 4,400 B. 0.5x + 4y

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