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A company that produces both copper and nickel owns two mines whose ore contains both minerals. Mine 1 costs $3,000 per day and can
A company that produces both copper and nickel owns two mines whose ore contains both minerals. Mine 1 costs $3,000 per day and can produce up to 40 tons of copper and 14 tons of nickel per day. Mine 2 costs $10,000 per day and can produce of to 15 tons of copper and 35 tons of nickel per day. The company must provide 90 tons of copper per week and 140 tons of nickel per week, using ore from its two mines. The following table summarizes these data. Resource Daily tons of copper Daily tons of nickel Daily operating costs Mine 1 40 14 $3,000 Mine 2 15 35 $10,000 Weekly Requirement (tons) 90 140 Mine I cannot be operated for more than five days a week. Similarly, Mine 2 cannot be operated for more than five days a week. The company seeks to minimize its total operating costs by choosing how much copper and nickel should be produced by each of its mines. Decision Variables: Let X, number of days per week that mine 1 is operated, and Let X= number of days per week that mine 2 is operated. . Objective Function: The total weekly cost can be represented as a linear function of these decision variables. Constraints: The constraints can be represented by linear combinations of these decision variables. (a) (1.0 points) What is the objective function? (b) (2.0 points) What are the six constraints? 7. (0.5 points) The prior problem was about deciding how much each mine should be operated, based on costs and their production of copper and nickel. But mining has potential social issues in addition to costs and production. (a) (0.25 points) Identify one social issue that may differ between the mines. (b) (0.25 points) Explain how that social issue could influence how much each mine is operated (i.e., increase or decrease operating days / production) and explain that rationale behind the connection to mining and the direction of influence.
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a Minimize 3000X1 10000X2 Subject to X1 X2 5 40X1 15X2 90 14X1 35X2 140 X1 0 X2 0 The objective function is to minimize the total weekly cost which is ...Get Instant Access to Expert-Tailored Solutions
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