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a} Consider the implicitly defined surface S = {(33, y, z) : f(:L', y, 2) = 3}, where f(:c, y, z) = 3:2 yz3 +

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a} Consider the implicitly defined surface S = {(33, y, z) : f(:L', y, 2) = 3}, where f(:c, y, z) = 3:2 yz3 + Sin(4y) l z. It is a fact that f(1, 0, 2) = 3 (you do not have to check this} and so the point (1, U, 2) is on the surface S. The curve t) 2 (ma), y), z(t)) lies on this implicitly dened surface. Suppose that - 'F(0) : (1, 0, 2) - 39(0) : 2 - z'(0) = 2 Compute 93(0). [Hintz Derivatives are related to tangents] b} Suppose that {1:4 + y2 ya: : 5. Compute %. It can be left implicit (i.e. you can have both :1: and y's in the answer)

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