A consumer advocacy group published a study of labeling of seafood sold in three U.S. states. The study found that 12 of the 22 "red snapper" packages tested were a different kind of fish. Assume that the study used a simple random sample. Complete parts a through below. a) Are the conditions for creating a confidence interval satisfied? Explain. OA OB. Ooc. O D. No, because the sample is a simple random sample, the sample proportion is between 10% and 90%, and there are at least 20 "successes" and 20 "failures." Yes, because the sample is a simple random sample, the sample is less than 10% of the population, and there are at least 10 "successes" and 10 "failures." No, because the sample is a simple random sample, the sample is less than 10% of the population, and there are at least 10 "successes" and 10 "failures." Yes, because the sample is a simple random sample, the sample proportion is between 10% and 90%, and there are at least 20 "successes" and 20 "failures." b) Construct a 95% confidence interval for the proportion of "red snapper" packages that were a different kind of fish. ( (Round to three decimal places as needed.) c) Explain what the confidence interval from part (b) says about "red snapper" sold in these three states. Select the correct choice below and fill in the answer boxes within your choice. (Round to one decimal place as needed.) O A. One is 95% confident that between | |% and | |% of all "red snapper" sold in food stores and restaurants in these three states is not actually red snapper. O B. Ninety-five percent of the time, the true proportion of "red snapper" sold in these three states that is falsely labeled is between | % and | %. O C. Oneis 95% confident that between | |% and | |% of all "red snapper" purchased for the study in these three states was not actually red snapper. O D. There is a 95% chance that the probability of any given "red snapper" sold in these three states being actual red snapper is between ' % and | %. A waitress believes the distribution of her tips has a model that is slightly skewed to the left, with a mean of $8.30 and a standard deviation of $4.10. She usually waits on about 50 parties over a weekend of work. a) Estimate the probability that she will earn at least $450. b) How much does she earn on the best 5% of such weekends? - - a) P(tips from 50 parties > $450) = (Round to four decimal places as needed.) b) The total amount that she earns on the best 5% of such weekends is at least $ (Round to two decimal places as needed.)