A corporation makes a payment of $2.76 million at the end of 2017 for services rendered by a large database company. With an annual interest rate of 10%, what annual payments at the end of years 2017 through 2023 will be equivalent to $2.76 million at the end of 2017 ? \begin{tabular}{|c|c|c|c|c|c|c|} \hline \multicolumn{7}{|c|}{ Discrete Compounding: I=10%} \\ \hline & \multicolumn{2}{|c|}{ Single Payment } & \multicolumn{4}{|c|}{ Uniform Series } \\ \hline & \begin{tabular}{l} Compound \\ Amount \\ Factor \end{tabular} & \begin{tabular}{l} Present \\ Worth Factor \end{tabular} & \begin{tabular}{c} Compound \\ Amount \\ Factor \end{tabular} & \begin{tabular}{c} Present \\ Worth Factor \end{tabular} & \begin{tabular}{l} Sinking \\ Fund \\ Factor \end{tabular} & \begin{tabular}{l} Capital \\ Recovery \\ Factor \end{tabular} \\ \hlineN & \begin{tabular}{c} To Find F \\ Given P \\ F/P \end{tabular} & \begin{tabular}{l} To Find P \\ Given F \\ P/F \end{tabular} & \begin{tabular}{c} To Find F \\ Given A \\ F/A \end{tabular} & \begin{tabular}{c} To Find P \\ Given A \\ P/A \end{tabular} & \begin{tabular}{l} To Find A \\ Given F \\ A/F \end{tabular} & \begin{tabular}{c} To Find A \\ Given P \\ A/P \end{tabular} \\ \hline 1 & 1.1000 & 0.9091 & 1.0000 & 0.9091 & 1.0000 & 1.1000 \\ \hline 2 & 1.2100 & 0.8264 & 2.1000 & 1.7355 & 0.4762 & 0.5762 \\ \hline 3 & 1.3310 & 0.7513 & 3.3100 & 2.4869 & 0.3021 & 0.4021 \\ \hline 4 & 1.4641 & 0.6830 & 4.6410 & 3.1699 & 0.2155 & 0.3155 \\ \hline 5 & 1.6105 & 0.6209 & 6.1051 & 3.7908 & 0.1638 & 0.2638 \\ \hline 6 & 1.7716 & 0.5645 & 7.7156 & 4.3553 & 0.1296 & 0.2296 \\ \hline 7 & 1.9487 & 0.5132 & 9.4872 & 4.8684 & 0.1054 & 0.2054 \\ \hline 8 & 2.1436 & 0.4665 & 11.4359 & 5.3349 & 0.0874 & 0.1874 \\ \hline 9 & 2.3579 & 0.4241 & 13.5795 & 5.7590 & 0.0736 & 0.1736 \\ \hline 10 & 2.5937 & 0.3855 & 15.9374 & 6.1446 & 0.0627 & 0.1627 \\ \hline \end{tabular}