A cubical piece of heat-shield tile from the space shuttle measures 0.10 m on a side and has a thermal conductivity of 0.065 J/(s m C). The outer surface of the tile is heated to a temperature of 1,296 C, while the inner surface is maintained at a temperature of 22 C. Consider the amount of heat that flows from the outer to the inner surface of the tile in 4.0 minutes. If this amount of heat were transferred to 4.0 kg of liquid water, by how many Celsius degrees would the temperature of the water change (rise)? Please round your answer to three decimal places. Equation: The heat conducted during time t (you must convert t to seconds) through the length L of the cubical heat-shield (with cross-sectional area 4 = 12) is: Q kA(T-T)t L k is the thermal conductivity, To is the temperature of the outer surface of the tile and T, is the temperature of the inner surface of the tile. Use this heat, Q, to find the change in temperature of the water AT by using this equation: Q mc AT. Take the specific heat of water, c = 4186 J/kg. Co.