The current in a 25-mH inductor is given by the expressions i(t)= -10e-4 +10 A, t>0 L lllll + Find (a) the voltage across the inductor, (b) the final energy trapped (stored) in it. a. V(t) = 1000 e 4 mV and Wt-1.25.J b. V(t) 10 e mV and Wt 0 J Oc. V(t)-40e at mV and Wt 0 J Od V(t)= 25 e 4 mV and Wt- 0 25 J Oe. None of them