A distribution of values is normal with a mean of176.2 and a standard deviation of 15.5. Find the probability that a randomly selected value is greater than 179.3. P(X> 179.3) = [:] Enter your answer as a number accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted. The time to complete an exam is approximately Normal with a mean of 38 minutes and a standard deviation of 7 minutes. The bell curve below represents the distribution for testing times. The scale on the horizontal axis is equal to the standard deviation. Fill in the indicated boxes. p- 30 [1-20 [1- 0 \"+0 \".140 \"Ii-30 A normal distribution has a mean of 30 and a standard deviation of 5. Find the probability that a randomly selected x-value from the distribution is in the given interval 50 50