A diverging lens of focal length -12.4 cm is placed 40.0 cm from a converging lens of unknown focal length. A 15.2 cm tall erect object is placed 25.3 cm in front of the diverging lens which is to produce an image on a screen that is twice the size of the original object but inverted.

• Where should the screen be located to produce a clear image?
• What is the focal length of the converging lens?
• What is the height of the intermediate image formed by the diverging lens
• If the screen is removed and the image is viewed using your eyes instead, what angular magnification would result from placing your eyes 40 cm from the final image?

Plz draw the picture and write down the detail. Thanks a lot !!!!