A E = 12,000 N/C 40 mm A charge of q = 1.5/C and mass 2g is released from rest on the left side of the parallel capacitor. a) Find the voltage difference across the capacitor. b) Use Conservation of Energy to find the kinetic energy of the charge when it strikes the other plate. Recall that AU = qAV, where U is the electric potential energy. c) Find the speed of the charge when it strikes the other plate. Recall that KE = ~mv2 d) Find the time it takes the charge to cross the capacitor. Note that it travels with constant acceleration, not constant velocity