A) final speed=363 m/s and potential difference 1729.3 volts and magnitude E=3.511 x10^4 N/C and acceleration=1.35x10^6 m/s^2 and Area=0.028 and q=8.70x10^-9 and d=0.049 m and mass=6.70x10^-20 kg and

find : The negative charge in Part D is initially placed close the Negative plate of the capacitor and is released from rest. What will be its speed when it reaches the Positive plate? The separation between the two plates is d = 0.049 m.

B) what will be its speed when it reaches the MIDDLE POINT between the two plates? Solve this using the conservation of energy.

C)The mass of the negative charge changes to 4.8010²⁰ kgkg (but its charge remains the same as above). It is initially placed close the Negative plate of the capacitor and is released from rest. What will be its speed when it reaches the Positive plate? Solve this using the conservation of energy.